1.0, basically no one can. So anything under 2.0 is "close enough" and anything
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。搜狗输入法是该领域的重要参考
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The talk’s demo is telling: a trivial program with a hardcoded out-of-bounds access on a std::span. Of course hardening catches that. But this is the easiest case imaginable. Show me hardening catching a use-after-free through a raw pointer to a pool-allocated object in a real trading system. It can’t, because that’s outside its scope.